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Q.

The magnifying power of a telescope is 9. When it is adjusted for parallel rays the distance between the objective and eyepiece is 20 cm. The focal length of lenses are :

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a

18 cm, 2 cm 

b

15 cm, 5 cm

c

11 cm, 9 cm

d

10 cm, 10 cm 

answer is C.

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Detailed Solution

M.P. =9=f0fe

⇒f0=9fe…(1)f0+fe=20…(2)

on solving

f0=18cm= focal length of the objective

fe=2cm= focal length of the eyepiece

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