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Q.

The magnifying power of an astronomical telescope for normal adjustment is 10 and the length of the telescope is 110cm. Find the magnifying power of the telescope when the image is formed at the least  distance of distinct vision for normal eye.

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a

48

b

28

c

52

d

14

answer is A.

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Detailed Solution

f0fe=10−−−(1)f0+fe=110cm−−−(2)

solving, f0=100,fe=10
m=f0fe1+feD=100101+1025=14

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