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The magnitude of a given vector with end points (4, -4, 0) and (-2, -2, 0) must be

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$5 \sqrt{2}$

$2 \sqrt{10}$

answer is D.

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Detailed Solution

$\vec{r} = \vec{r_{2}} - \vec{r_{1}}$ = ( $- 2 \hat{i} - 2 \hat{j} + o \hat{k}$ ) - $(4 \hat{i} - 4 \hat{j} + 0 \hat{k})$

$\Rightarrow$ $\vec{r} = - 6 \hat{i} + 2 \hat{j} + 0 \hat{k}$

$∴ | \vec{r} | = \sqrt{{(- 6)}^{2} + {(2)}^{2} + 0^{2}}$

= $\sqrt{36 + 4} = \sqrt{40} = 2 \sqrt{10}$

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