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Q.

The magnitude of acceleration of the body in uniform circular motion

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a

$a_{c} = \frac{v^{2}}{R}$

b

$a_{c} = \frac{v}{R}$

c

$a_{c} = \frac{v}{R^{2}}$

d

$a_{c} = \frac{2 v^{2}}{R}$

answer is A.

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Detailed Solution

$\begin{aligned} F_{c} = m \times \frac{v^{2}}{R} (a_{c} = \frac{v^{2}}{R}) \\ F = ma \\ ma = m \frac{v^{2}}{R} \\ a_{c} = \frac{v^{2}}{R} \end{aligned}$

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