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Q.

The magnitude of electric field intensity at a distance x from a point charge q is E. An identical charge is placed at a distance to 2x from it. Then the magnitude of the force it experiences, is:

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a

qE

b

2qE

c

$\frac{qE}{2}$

d

$\frac{qE}{4}$

answer is D.

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Detailed Solution

Electric field intensity, $E = \frac{q}{4 {πe}_{0} x^{2}}$

Intensity at a distance 2x is, $E' = \frac{q}{4 {πe}_{0} {(2 x)}^{2}} = \frac{E}{4}$

Therefore, force = $\frac{qE}{4}$

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