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Q.

The magnitude of electric intensity E Such that an electron placed in an electric field would experience an electric force equal to its weight is

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a

$5.6 \times 10^{- 8} N/C$

b

$5.6 \times 10^{- 10} N/C$

c

$5.6 \times 10^{- 7} N/C$

d

$5.6 \times 10^{- 11} N/C$

answer is D.

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Detailed Solution

$F = mg = qE \Rightarrow \frac{mg}{q}$

$= \frac{9 \times 10^{- 31} \times 10}{1.6 \times 10^{- 19}} = 5.6 \times 10^{- 11} N/C$

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The magnitude of electric intensity E Such that an electron placed in an electric field would experience an electric force equal to its weight is