The magnitude of force acting on a body varies with time as shown in figure. The magnitude of total impulse of the force on the body from $t = 4 μ s to t = 16 μ s$ is

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$8.4 \times 10^{- 3} Ns$

$6 \times 10^{- 3} Ns$

$7. 6 \times 10^{- 3} Ns$

$5 \times 10^{- 3} Ns$

answer is B.

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Detailed Solution

Impulse is area under the curve of Force-time graph.

$\begin{array}{l} J = \frac{1}{2} (200 + 800) \times 2 \times 10^{- 6} + \frac{1}{2} \times 10 \times 800 \times 10^{- 6} \\ J = 0.001 + 0.004 = 0.005 Ns \end{array}$

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