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Q.

The magnitude of magnetic field due to a dipole of magnetic moment ${1.2 Am}^{2}$ at a point 1 m away from it in a direction making an angle of $60^{0}$ with the dipole axis is

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a

${3.2×10}^{-7} T$

b

${3.2×10}^{-6} T$

c

${1.6×10}^{-7} T$

d

${1.6×10}^{-6} T$

answer is A.

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Detailed Solution

The magnitude of the magnetic field at any point is
$B= \frac{μ_{0}}{4 π} . \frac{M}{r^{3}} \sqrt{1 + 3 \cos^{2} θ}$
Given : $M = 1.2 A m^{2}; r = 1 m; θ = 60^{0}$
$\Rightarrow B = (10^{- 7}) (\frac{1.2}{1}) \sqrt{1 + 3 \cos^{2} 60}$
$\Rightarrow B = 1.6 \times 10^{- 7} T$ .

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