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Q.

The magnitude of the force of gravity between two identical objects is given by $F_{0}$ . If the mass of each object is doubled but the distance between them is halved, then the new force of gravity between the objects will be

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a

{16F}_{0}

b

F_{0}

c

{4F}_{0}

d

\frac{F_{0}}{2}

answer is A.

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Detailed Solution

F_{0} = \frac{Gmm}{r^{2}} F_{1} = \frac{G \times 2m \times 2m}{{(r/2)}^{2}}

$\frac{F_{0}}{F_{1}} = \frac{{Gmm/r}^{2}}{{16Gmm/r}^{2}}$

$F_{1} = 16 F_{0}$

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