The magnitude of the magnetic field induction at the origin O due to a very long conductor carrying current i of the shape shown in fig. will be

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$- \frac{μ_{0} i}{4 πr} [i - \frac{π}{2} k]$

$\frac{μ_{0} i}{4 πr} [i + \frac{π}{2} k]$

$- \frac{μ_{0} i}{4 πr} [i + \frac{π}{2} k]$

$\frac{μ_{0} i}{4 πr} [i - \frac{π}{2} k]$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The magnetic field induction at O due to different parts of the conductor will be
$\begin{array}{l} B_{0} = B_{1} + B_{2} + B_{3} \\ = \frac{μ_{0} i}{4 πr} (- i) + \frac{μ_{0} i}{4 πr} (\frac{π}{2}) (- k) + 0 \\ = - \frac{μ_{0} i}{4 πr} [i + \frac{π}{2} k] \end{array}$

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE