The main scale of vernier calipers reads in mm and its vernier scale is divided into 8 divisions which coincide with 5 divisions of the main scale. When the two jaws touch each other, the zero of the vernier coincides with the zero of main scale. When a rod is tightly placed along its length between the jaws, it is observed that the zero of vernier scale lies just left to 36^th division of main scale and 4^th division of vernier scale coincides with one main scale division. The measured value is (in cm)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

3.65

3.66

3.55

3.56

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

M.S. reading 35 mm

X + 4V = nM

$X = nM - 4 (\frac{5}{8} M)$

X < 1 m for n = 3 only

So, $X = 3 - \frac{5}{2} = \frac{1}{2} mm$

$∴$ reading y = 35 + 0.5 mm

= 3.55 cm

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE