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The main scale of vernier calipers reads in mm and its vernier scale is divided into 8 divisions which coincide with 5 divisions of the main scale. When the two jaws touch each other, the zero of the vernier coincides with the zero of main scale. When a rod is tightly placed along its length between the jaws, it is observed that the zero of vernier scale lies just left to 36^th division of main scale and 4^th division of vernier scale coincides with one main scale division. The measured value is (in cm)

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3.66

3.55

3.65

3.56

answer is B.

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Detailed Solution

M.S. reading 35 mm

X + 4V = nM

$X = nM - 4 (\frac{5}{8} M)$

X < 1 m for n = 3 only

So, $X = 3 - \frac{5}{2} = \frac{1}{2} mm$

$∴$ reading y = 35 + 0.5 mm

= 3.55 cm

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