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Q.

The Markovnikov addition of HCl to propene involves the

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a

isomerization of 1-chloropropane

b

formation of an n-propyl cation

c

initial attack of a chloride ion

d

formation of an isopropyl carbocation

answer is D.

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Detailed Solution

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Markovnikov addition of HCl to propene results in the formation of 2-chloropropane.

The reaction as follows: This reaction involves the formation of carbocation and then the attack of chloride ion takes place.

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