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Q.

The mass and diameter of a planet are two times those of earth. If a seconds pendulum is taken to it, the time period of the pendulum in seconds is

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a

12

b

22

c

12

d

2

answer is C.

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Detailed Solution

T=2πgT1g;T2T1=g1g2,T1=2 secg1=GMR2,g2=G(2M)(2R)2=g12T2=T1g1g1/2=22sec

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