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Q.

The mass defect for the nucleus of helium is 0.0303 amu. The binding energy per nucleon in MeV is nearly

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a

28

b

7

c

4

d

1

answer is B.

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Detailed Solution

BE=Δm×931MeV=0.0303×931MeVBEA=0.0303×9314=7MeV

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