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Q.

The mass defect for the nucleus of nitrogen is 0.0572 amu the binding energy per nucleon in Mev is nearly

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a

2.8

b

3.8

c

4.8

d

1.8

answer is A.

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Detailed Solution

BE per nucleon_{$= \frac{B E}{A} = \frac{(Δ m)}{A} \times 931 M e v$}

_{$= \frac{0.0572 \times 931}{14} M e v$}

_{$= 3.8038 M e v$}

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