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The mass defect in a particular nuclear reaction is 0.3 grams. The amount of energy liberated in kilowatt hour is [Velocity of light = 3 × 10⁸ m/s]

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1.5 × 10⁶

2.5 × 10⁶

3 × 10⁶

7.5 × 10⁶

answer is D.

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Detailed Solution

$\begin{array}{l} E = Δ {mc}^{2} = 0 .3 \times 10^{- 3} \times 9 \times 10^{16} = 2 .7 \times 10^{13} J \\ = \frac{2 .7 \times 10^{13}}{36 \times 10^{5}} k W h = \frac{270}{36} \times 10^{6} = 7 .5 \times 10^{6} k W h \end{array}$

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