The mass m shown in the figure oscillates in simple harmonic motion with amplitude A. The amplitude of the point P is

$\begin{array}{l}\text{ Force in the spring 1 and spring 2 is same}.\\ \therefore {\mathrm{k}}_1{\mathrm{A}}_1={\mathrm{k}}_2{\mathrm{A}}_2\left(\mathrm{i}\right)\\ {\text{ \hspace{0.17em}and A}}_1+{\mathrm{A}}_2=\mathrm{A}\left(\mathrm{ii}\right)\\ \therefore {\mathrm{k}}_1{\mathrm{A}}_1={\mathrm{k}}_2\mathrm{A}-{\mathrm{k}}_2{\mathrm{A}}_1\\ \Rightarrow {\mathrm{A}}_1=\frac{{\mathrm{k}}_2}{{\mathrm{k}}_1+{\mathrm{k}}_2}.\mathrm{A}\end{array}$