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The mass of 2.43 L of ${CH}_{4} at 1.5$ atm and 27 $°$ C is

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3.0g

1.6g

2..4g

22.4g

answer is B.

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Detailed Solution

$PV = \frac{W}{m} RT$

$1.5 \times 2.43 = \frac{W}{16} \times 0.0821 \times 300$

$w = 2.36 g ≃ 2.4 g$

$∴ The mass of 2.43 L of {CH}_{4} at {CH}_{4} at 1.5 atm and 24 ° C is 2.4 g$

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