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Q.

The mass of a simple pendulum bob is 100 gm. The length of the pendulum is 1 m. The bob is drawn aside from the equilibrium position so that the string makes an angle of 60° with the vertical and let go. The kinetic energy of the bob while crossing its equilibrium position will be

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a

0.49 J

b

1 J

c

0.94 J

d

1.2 J

answer is A.

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Detailed Solution

K.Emean=P.Eextreme=mgl1-cosθ

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