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Q.

The mass of a sphere placed on a smooth horizontal surface is distributed non-uniformly. A horizontal force equal to weight of sphere is applied at a distance 'a' from centre of the sphere for a short time. The sphere is rotated by an angle θ but it behaves as if in stable equilibrium. Find the distance between centre and CG of the sphere:

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a

a tan θ

b

a cot θ

c

a cosec θ

d

a sec θ

answer is D.

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Detailed Solution

The sphere is in stable equilibrium. It will come back to original position after rotation. Rotating Moment = Fa. For stable equilibrium, 

Question Image

Restoring moment = Rotating moment
Since F=W,Wa=Fa
Let O be the centre and C and C' be the positions of CG before and after rotation.

OC=OC and CB=a........(from equation(i))

 In ΔOBC , OC'= CBcosecθ=acosecθ

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