The mass of ammonia in grams produced when $2.8 kg$ of dinitrogen quantitatively reacts with $1 kg$ of dihydrogen is ____.

$$\begin{gathered} N_2 + 3H_2\to 2{NH}_3 \\ 1 3 2 moles \\ no. of moles of N_2=\frac{2.8\times {10}^{3}g}{28}={10}^{2}moles \\ no. of moles of H_2=\frac{1\times {10}^{3}g}{2}=5\times {10}^{2}moles \end{gathered}$$

excess moles of H₂ represents, N₂ is limiting reagent

$\therefore$ mass of $\left({NH}_3\right)=2\times {10}^2\times 17g$

$=3400gm$

$=3.4Kg$

Hence the correct answer is 3400.