The mass of CaO that can be prepared by heating 200kg of limestone CaCO₃ which is 95%pure is

Explanation

Calculate the Mass of Pure CaCO₃ in the Limestone

Since the limestone is 95% pure, the mass of pure CaCO₃ is:

Mass of pure CaCO3 = 200 kg × 0.95 = 190 kg

Theoretical Yield of CaO from CaCO₃

The decomposition reaction of calcium carbonate is:

CaCO3 → CaO + CO2

From stoichiometry, 100 g of CaCO₃ yields 56 g of CaO.

Calculate the Mass of CaO Produced:

Using the proportion:

(56 g CaO / 100 g CaCO3) = (x g CaO / 190 kg CaCO3)

Solving for x:

x = (56 / 100) × 190 = 106.4 kg

Final Answer:

The mass of CaO obtained by heating 200 kg of 95% pure limestone is c) 106.4 kg