The mass of CO₂ obtained when 2g of pure limestone is calcined is

$$\begin{gathered} {\mathrm{CaCO}}_3\to \mathrm{CaO}+{\mathrm{CO}}_2 \\ 100\mathrm{gm} 44\mathrm{gm}. \\ 2\mathrm{g} ? \\ \mathrm{Mass} \mathrm{of} {\mathrm{CaCO}}_3\left(\mathrm{limestone}\right)=\frac{2}{100}\times 44=0.88\mathrm{g} \end{gathered}$$