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The mass of glucose (in gm) which is present in 500 gm of 0.1 m glucose solution is

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18.84 gr

8.84 gr

28.84 gr

9.00 gr

answer is B.

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Detailed Solution

Let mass of solute $= x grm m = 0 .1$
$0 .1 = \frac{x}{180} \times \frac{1000}{500 - x} 18 (500 - x) = 1000 x$
$9000 = 1018 x x = \frac{9000}{1018} = 8 .84 grm$

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