Q.

The mass of glucose that should be dissolved in 100g of water in order to produce the same lowering of vapor pressure as is produced by dissolving 1g of urea (molecular mass=60) in 50g of water is:

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answer is 6.

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Detailed Solution

Δpp0=xBnBnA=wB×mAmB×wA

wB×mAmB×wAglucose=wB×mAmB×wAurea

wB×18180×100=1×1860×50    or   wB=6g

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