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The mass of hydrogen atom is 1.66 × 10^–24g and Planck's constant is 6.64×10^–27erg-sec. The de Broglie wave-length of a hydrogen atom moving with a velocity half that of light is equal to

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$2.66 \times 10^{- 27} A °$

$2.66 . 10^{- 10} A °$

$2.66 \times 10^{- 13} A °$

$2.66 \times 10^{- 5} A °$

answer is A.

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Detailed Solution

$λ = \frac{h}{m v} = \frac{6.64 \times 10^{- 34}}{6.64 \times 10^{- 27} \times \frac{3}{2} \times 10^{8}} = 2.66 \times 10^{- 5} \times 10^{- 10} m = 2.66 \times 10^{- 5} A^{o}$

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