Book Online Demo
Check Your IQ
Try Test

Courses

Dropper NEET CourseDropper JEE CourseClass - 12 NEET CourseClass - 12 JEE CourseClass - 11 NEET CourseClass - 11 JEE CourseClass - 10 Foundation NEET CourseClass - 10 Foundation JEE CourseClass - 10 CBSE CourseClass - 9 Foundation NEET CourseClass - 9 Foundation JEE CourseClass -9 CBSE CourseClass - 8 CBSE CourseClass - 7 CBSE CourseClass - 6 CBSE Course

Q.

The mass of hydrogen molecule is 3.32 ×10-27 kg. If 1023 hydrogen molecules strike per second at 2 cm2 area of a rigid wall at an angle of 45° from the normal and rebound back with a speed of 1000 ms-1, then the pressure exerted on the wall is

Question Image

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

0.23 × 106 Pa

b

23.4 × 103 Pa

c

0.23 × 103 Pa

d

2.34 × 103 Pa

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

F = rate of change of momentum =ΔpΔt=(nm)(2vcosθ)

Pressure, p=FA=(nm)(2vcosθ)A

                    =1023×3.32×10-27×2×1000×cos45°2×10-4

                     =2.34 × 103 Nm-2   or   Pa

Watch 3-min video & get full concept clarity

hear from our champions

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

Related Blogs
Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
Result Producing online coaching for JEE/NEET of south India
Largest All India Test Series for JEE/NEET
Best Books for IIT JEE
Best Books for NEET
whats app icon