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The mass of neutron and proton are 1.0087 amu and 1.0073 amu respectively and if two protons and two neutrons form a nucleus of helium whose mass is 4.0015 amu, Then find the binding energy of helium nucleus.

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7.1 Mev

28.4 ev

28.4 Mev

26.2 Mev

answer is C.

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Detailed Solution

$\begin{array}{l} Binding energy = [2 (1 .0087 + 1 .0073) - 4 .0015] \times 931 .5 Mev \\ = 28 .41 Mev \end{array}$

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