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Q.

The mass of neutron and proton are 1.0087 amu and 1.0073 amu respectively and if two protons and two neutrons form a nucleus of helium whose mass is 4.0015 amu, Then find the binding energy of helium nucleus.

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a

7.1 Mev

b

28.4 ev

c

28.4 Mev

d

26.2 Mev

answer is C.

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Detailed Solution

Binding energy=[2(1.0087+1.0073)−4.0015]×931.5 Mev                                                         =28.41 Mev

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