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The mass of oxygen present in $0.5$ mole of $P_{4} O_{10}$ is (Atomic weight of $P$ is 31 and $O$ is 16 )

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$80 g$

$124 g$

$240 g$

$160 g$

answer is B.

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Detailed Solution

Mass of oxygen present in 1 mole of $P_{4} O_{10}$ $16 \times 10 = 160 g m$

Similarly, using unitary method,

For $0.5$ moles of $P_{4} O_{10}$

$\frac{160}{2}$ = 80g

Hence option B is the correct answer.

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