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The mass of the planet Jupiter is $1.9 \times 10^{27} kg$ and that of the Sun is $1.99 \times 10^{30} kg$ . The mean distance of Jupiter and the Sun is $7.8 \times 10^{11} m$ . What is the gravitational force exerted by the Sun on Jupiter?

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4.15 \times 10^{23} N

4.15 \times 10^{20} N

4.15 \times 10^{16} N

4.15 \times 10^{12} N

answer is A.

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Detailed Solution

The gravitational force exerted by the Sun on the Jupiter is

1.9 \times 10^{27} kg

.
Given:
The mass of the planet Jupiter is

m_{1} = 1.9 \times 10^{27} kg

The mass of the Sun is

m_{2} = 1.99 \times 10^{30} kg

The mean distance of Jupiter and Sun is

r = 7.8 \times 10^{11} m

According to Newton’s Law of Gravitation, we get the gravitational force (F)

F = \frac{G {m_{1} m}_{2}}{r^{2}}

F = \frac{6.67 \times 10^{- 11} \times 1.9 \times 10^{27} \times 1.99 \times 10^{30}}{{(7.8 \times 10^{11})}^{2}}

F = 4.15 \times 10^{23} N

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