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The mass of ${CO}_{2}$ obtained when 2g of pure limestone is heated

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44 g

0.88 g

0.22 g

8.8 g

answer is C.

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Detailed Solution

${CaCO}_{3} \to CaO + {CO}_{2}$

$100 g of {CaCO}_{3} = 44 g of {CO}_{2}$

$2 g of {CaCO}_{3} = ? of {CO}_{2}$

$= \frac{2}{100} \times 44$

$= \frac{22}{25} = 0.88 g .$

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