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Q.

The mass of $({CO}_{2})$ that can be prepared by treating 100 g of limestone with HCl is…
${CaCO}_{3} + 2 HCl \to {CaCl}_{2} + H_{2} O + {CO}_{2}$

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a

66g

b

44g

c

88g

d

22g

answer is B.

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Detailed Solution

${CaCO}_{3} + 2 HCl \to {CaCl}_{2} + H_{2} O + {CO}_{2}$

1 mole of ${CaCO}_{3}$ gives 1 mole of ${CO}_{2}$

100g of ${CaCO}_{3}$ ........44g of ${CO}_{2}$

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