Q.

The mass per unit area of a circular disc (of negligible thickness) varies with distance
from centre ‘r’ as ρ=ρ01+r where ρ0 is a constant. Its moment of Inertia about an axis passing through center perpendicular to plane is πρR410(Y+4R). Then Y=_______ (taken the radius of the disc as R)

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answer is 5.

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Detailed Solution

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Consider a ring of radius ‘r’ and width 'dr' mass of ring element dm=ρ×2πr dr; 

dm=ρ0(1+r)2πrdr 

 MI 0f  discc I=0R  dI=0R r2dm=πρ0R410[5+4R]

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