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Q.

The masses of neutron and proton are 1.0087 a.m.u. and 1.0073  a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV)

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a

14.2  MeV

b

27.3  MeV

c

28.4  MeV

d

 20.8  MeV

answer is A.

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Detailed Solution

B.E.= ∆mc2 = =[2(1.0087+1.0073)-4.0015]=28.4 MeV

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The masses of neutron and proton are 1.0087 a.m.u. and 1.0073  a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV)