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Q.

The masses of the two blocks A and B are 2 m and 3 m. They are placed on smooth horizontal surface and are connected by a light spring. The two blocks are given velocities as shown when the spring is relaxed.

Question Image
 Column – I Column – II
AMinimum magnitude of velocity of AVAmin  during motionPV
BMaximum magnitude of velocity of   AVAmaxduring motionQv5
CMaximum magnitude of velocity of  BVBmax  during motionR0
DVelocity of centre of mass  vcm of the system comprised of blocks A, B and springS7v5
  Tv3

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a

A-R ;B-Q; C-S; D-P

b

A-R; B-S; C-Q; D-P

c

A-S ;B-R ; C-Q; D-P

d

A-R;B-S; C-P; D-Q

answer is A.

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Detailed Solution

vcm=3mv2mv5m=v5  

In COM frame 
 Initial velocity of A=vv5=6v5   to right  
 Initial velocity of B=vv5=45v=45v   to left  

Blocks are doing SHM in COM frame with initial position as equilibrium position velocity variation of A in ground frame, considering  right as +ve  from  4v5+v5=vto4v5+v5=3v5

SovAmax=vandvAmax=0

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