The material used for fuse wire should have:

We must comprehend that a fuse wire is used in a circuit to monitor the current in the circuit before we can answer this question. It operates according to the heating law of Joule. A lot of heat is produced when a very high current—which might harm other circuit elements—passes through the fuse wire, which causes the fuse wire to melt and trip the circuit.
According to the Joule's rule of heating, the heat generated per second H in a wire of resistance R carrying a current I may be calculated as follows:

$H=I^{2}R$
The fuse is a safety component that is connected in series at the beginning of an electrical circuit to monitor any current overload. Other electrical components in the circuit may be harmed if there is an excess of current flowing through it.
This is avoided by the fuse thanks to the use of the heating law of Joule.
According to the Joule's rule of heating, the heat generated per second H in a wire of resistance R carrying a current I may be calculated as follows:
$H=I^{2}R---\left(1\right)$

When an overload current is flowing, a lot of heat is produced in the fuse wire, which melts the wire and breaks the circuit, stopping the flow of the overload current.
According to (1), a fuse wire should have a high resistance so that a lot of heat is produced and it may more easily reach its melting point. A high resistance also reduces the current flowing in the circuit relative to what it would have been without it.
Additionally, a fuse wire has to have a low melting point so that it may readily be accessed and melted to break. If the melting point is too high, it will use a significant amount of current over an extended period of time before the fuse melts and breaks. The other electrical components may also be harmed in the meantime due to the excessive current.

Hence, the correct answer is option A.