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The maximum allowable level of Nitrates in drinking water as set by U.S. is 45mg ${NO}_{3}^{-}$ ions per dm³, the level in ppm is

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answer is C.

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Detailed Solution

$10^{3} \to 45 \times 10^{- 3} gr; 10^{6} \to ? (x) (x) = \frac{10^{6} x 45 x 10^{- 3}}{10^{3}} (x) = 45 p p m$

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