The maximum and minimum distances of a comet from the sun are 8×1012 m and 1.6×1012m. If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest?

By conservation of angular momentum mvr = constant vmin×rmax=vmax×rmin∴ vmin=60×1.6×10128×1012=605=12m/s

The maximum and minimum distances of a comet from the sun are 8×1012 m and 1.6×1012m. If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest?

By conservation of angular momentum mvr = constant vmin×rmax=vmax×rmin∴ vmin=60×1.6×10128×1012=605=12m/s

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The maximum and minimum distances of a comet from the sun are $8 \times 10^{12}$ m and $1.6 \times 10^{12}$ m. If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest?

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By conservation of angular momentum mvr = constant

$\begin{array}{l} v_{min} \times r_{max} = v_{max} \times r_{min} \\ ∴ v_{min} = \frac{60 \times 1 .6 \times 10^{12}}{8 \times 10^{12}} = \frac{60}{5} = 12 m / s \end{array}$

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The maximum and minimum distances of a comet from the sun are 8×1012 m and 1.6×1012m. If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest?

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The maximum and minimum distances of a comet from the sun are $8 \times 10^{12}$ m and $1.6 \times 10^{12}$ m. If its velocity when nearest to the sun is 60 m/s, what will be its velocity in m/s when it is farthest?