Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

The maximum current that can be measured by a galvanometer of resistance 40Ω is 10 mA .it is converted into a voltmeter that can read up to 50V. The resistance to be connected in series with the galvanometer is ---(in ohm)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

5040Ω

b

4960Ω

c

4050  Ω

d

2010Ω

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

R=VigG=5010×10340=500040=4960Ω

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon