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Q.

The maximum electric field of a plane electromagnetic wave is 88 V/m. The average energy density is

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a

13.7 ×10^-8 Jm^-3

b

6.8 ×10^-8 Jm^-3

c

3.4 ×10^-8 Jm^-3

d

1.7 ×10^-8 Jm^-3

answer is A.

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Detailed Solution

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Average energy density = $\frac{1}{2} \in_{0} {E_{0}}^{2}$

$= \frac{1}{2} x 8.8 x 10^{- 12} x 88 x 88 = 3.4 x 10^{- 8} {Jm}^{- 3}$

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