The maximum error in the measurement of resistance, current and time for which current flows in an electrical circuit are 1%, 2% and 3% respectively. The maximum percentage error in the detection of the dissipated heat will be:

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answer is D.

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Detailed Solution

$\begin{array}{l} E_{H} = I^{2} R \times t \\ \frac{ΔE}{E} \times 100 = \frac{2 ΔI}{I} \times 100 + \frac{ΔR}{R} \times 100 + \frac{ΔT}{T} \times 100 \\ = 2 \times 2 + 1 + 3 = 8 \end{array}$

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