The maximum number of isomers for an alkene with the molecular formula $C_{4} H_{8}$ is

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answer is C.

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Detailed Solution

The four isomers are ${CH}_{2} = CH - {CH}_{2} - {CH}_{3}$ , cis- and trans-forms of ${CH}_{3} - CH = CH - {CH}_{3}$ and ${({CH}_{3})}_{2} C = {CH}_{2}$ .

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