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Q.

The maximum number of possible interference minima can be observed on screen for slit separation equal to twice the wavelength in Young’s double slit experiment is

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a

Infinite

b

Five

c

Three

d

Four

answer is D.

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Detailed Solution

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As the distance between the slit is twice the wave length on both the side of the central maxima two maxima will form in between two maxima two minima on either side and total five maxima including central and four minima 

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