The maximum possible number of points of intersection of 7 straight lines and 5 circles is:

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111

109

107

105

answer is A.

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Detailed Solution

Maximum possible number of points of intersection of 7 lines is $^{7} C_{2} = 21$

Maximum possible number of points of intersection of 5 circles in $2 (^{5} C_{2}) = 20$

$[∵$ two circles can intersect in two distinct points.]

Maximum possible number of points of intersection of 5 circles and 7 lines is 2(5) (7) = 70

Thus, maximum possible number of points of intersection is 21 + 20 + 70 = 111.

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