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The maximum speed with which a car of mass 1000 kg can move on a circular track without slipping on a horizontal road having coefficient of static friction 0.5 is 7 ms^-1. What is the static frictional force between the car tyres and the road when the speed of the car on the same track is 5 ms^-1?

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4900 N

250 N

2500 N

Zero

answer is B.

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Detailed Solution

For maximum velocity

$\frac{{mv}^{2}}{r} = μmg r = \frac{v^{2}}{μg} = \frac{7 \times 7}{0.5 \times 9.8} = 10 m$

$when speed is 5 m / s frictional force = \frac{{mv}^{2}}{r}$

$\frac{1000 \times 5 \times 5}{10} = 2500 N$

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