The maximum vertical height to which a man can throw a ball is 136 m. The maximum horizontal distance upto which he can throw the same ball is :

Given:

• Maximum vertical height = 136 m
• Maximum horizontal distance (range) needs to be determined.

The formula for maximum vertical height H is:

H = (vy²) / (2g)

where v_y is the vertical component of the initial velocity, and g is the acceleration due to gravity (9.8 m/s²).

For horizontal range R, the formula is:

R = (vx²) / g

where v/x is the horizontal component of the velocity.

In projectile motion, the range R is double the maximum height H when the launch angle is 45°.

Hence,

R = 2 × H = 2 × 136 = 272 m

Final Answer

Thus, the correct answer is 272 m.