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Q.
The maximum wavelength of a beam of light that can be used to produce photo electric effect on a metal is 250 nm. The energy of the electrons in Joule, emitted from the surface of the metal when a beam of light of wavelength 200 nm is used [h = 6.62×10-34 Js, C = 3 × 108 ms-1]
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a
69.81 × 10-22
b
89.61 × 10-22
c
18.96 × 10-20
d
19.86 × 10-20
answer is D.
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Detailed Solution
The energy of the electrons emitted from the surface of the metal when a beam of light of wavelength 200 nm is used is:
19.86 × 10-20 J
Detailed Calculation:
- Maximum wavelength allowed for photoelectric effect: λmax = 250 nm
- Threshold frequency (ν0):
Using the formula:
ν0 = c / λmax
Substitute the given values:
c = 3 × 108 m/s, λmax = 250 nm = 250 × 10-9 m
ν0 = (3 × 108) / (250 × 10-9)
ν0 = 1.2 × 1015 Hz - Threshold energy (Work function):
Using the formula:
E0 = h × ν0
Substitute the given values:
h = 6.62 × 10-34 J·s, ν0 = 1.2 × 1015 Hz
E0 = (6.62 × 10-34) × (1.2 × 1015)
E0 = 7.944 × 10-19 J - Energy of incident light:
Using the formula:
E = h × c / λ
Substitute the given values:
λ = 200 nm = 200 × 10-9 m
E = (6.62 × 10-34) × (3 × 108) / (200 × 10-9)
E = (6.62 × 3) × 10-19 / 200
E = 9.93 × 10-19 J - Kinetic energy of emitted electrons:
Using the formula:
KE = E - E0
Substitute the values:
KE = (9.93 × 10-19) - (7.944 × 10-19)
KE = 1.986 × 10-19 J
KE = 19.86 × 10-20 J
Concept:
- The photoelectric effect depends on the energy of incident light.
- If the light energy exceeds the threshold energy, electrons are emitted.
- Kinetic energy of electrons = Energy of incident light - Threshold energy.
- Planck's constant (h) and the speed of light (c) are used to calculate photon energy.
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