Q.

The maximum wavelength of a beam of light that can be used to produce photo electric effect on a metal is 250 nm. The energy of the electrons in Joule, emitted from the surface of the metal when a beam of light of wavelength 200 nm is used [h = 6.62×10-34 Js, C = 3 × 108 ms-1]

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a

69.81 × 10-22

b

89.61 × 10-22

c

18.96 × 10-20

d

19.86 × 10-20

answer is D.

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Detailed Solution

The energy of the electrons emitted from the surface of the metal when a beam of light of wavelength 200 nm is used is:

19.86 × 10-20 J

Detailed Calculation:

  1. Maximum wavelength allowed for photoelectric effect: λmax = 250 nm
  2. Threshold frequency (ν0): 
    Using the formula: 
    ν0 = c / λmax
    Substitute the given values: 
    c = 3 × 108 m/s, λmax = 250 nm = 250 × 10-9
    ν0 = (3 × 108) / (250 × 10-9
    ν0 = 1.2 × 1015 Hz
  3. Threshold energy (Work function): 
    Using the formula: 
    E0 = h × ν0
    Substitute the given values: 
    h = 6.62 × 10-34 J·s, ν0 = 1.2 × 1015 Hz 
    E0 = (6.62 × 10-34) × (1.2 × 1015
    E0 = 7.944 × 10-19 J
  4. Energy of incident light: 
    Using the formula: 
    E = h × c / λ
    Substitute the given values: 
    λ = 200 nm = 200 × 10-9
    E = (6.62 × 10-34) × (3 × 108) / (200 × 10-9
    E = (6.62 × 3) × 10-19 / 200 
    E = 9.93 × 10-19 J
  5. Kinetic energy of emitted electrons: 
    Using the formula: 
    KE = E - E0
    Substitute the values: 
    KE = (9.93 × 10-19) - (7.944 × 10-19
    KE = 1.986 × 10-19
    KE = 19.86 × 10-20 J

Concept:

  • The photoelectric effect depends on the energy of incident light.
  • If the light energy exceeds the threshold energy, electrons are emitted.
  • Kinetic energy of electrons = Energy of incident light - Threshold energy.
  • Planck's constant (h) and the speed of light (c) are used to calculate photon energy.
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