The Maxwell’s equation

$\int \overrightarrow{B}\overrightarrow{dl}={\mu }_0\left[I+{\epsilon }_0\frac{d{\varphi }_{\epsilon }}{dt}\right]$  is a statement of

$\int \overrightarrow{\mathrm{B}}\cdot \overrightarrow{\mathrm{dl}}={\mathrm{\mu }}_0\left[\mathrm{I}+{\mathrm{\epsilon }}_0\frac{{\mathrm{d\varphi }}_{\mathrm{\epsilon }}}{\mathrm{dt}}\right] \mathrm{is} \mathrm{modified} \mathrm{Ampere}\text{'}\mathrm{s} \mathrm{law}$

$$\begin{gathered} \int \overrightarrow{\mathrm{B}}\cdot \overrightarrow{\mathrm{dl}}={\mathrm{\mu }}_0\left[\mathrm{I}\right] \mathrm{is} \mathrm{normal} \mathrm{Ampere}\text{'}\mathrm{s} \mathrm{law} \mathrm{wher} \mathrm{I} \mathrm{is} \mathrm{the} \mathrm{conduction} \mathrm{current} \\ \mathrm{he} \mathrm{has} \mathrm{also} \mathrm{considered} \mathrm{the} \mathrm{displacment} \mathrm{current} \mathrm{which} \mathrm{is} \left[{\mathrm{\epsilon }}_0\frac{{\mathrm{d\varphi }}_{\mathrm{\epsilon }}}{\mathrm{dt}}\right] \end{gathered}$$