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Q.

The mean and variance of 20 observations are found to be 10 and 4, respectively. On rechecking, it was found that an observation 9 was incorrect and the correct observation was 11. Then the correct variance is:

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a

4.02 

b

4.01

c

3.99

d

3.98

answer is C.

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Detailed Solution

xi20=10  xi220-100=4  (ii)xi2=104×20=2080 Actual mean =200-9+1120=20220

 Actual Variance =2080-81+12120-202202=212020-(10.1)2=106-102.01=3.99

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