The mean and variance of the data 4, 5, 6, 6, 7, 8, x, y, where x<y are 6 and 94 respectively. Then x4+y2 equal to

x¯=6,σ2=94x<y4,5,6,6,7,8,,x,yx¯=36+x+y8x+y=12∑xi2n−x¯2=94x2+y2+2268=94+36x2+y2=80, xy=32X=4,y=8=x4+y2=256+64=320

The mean and variance of the data 4, 5, 6, 6, 7, 8, x, y, where x<y are 6 and 94 respectively. Then x4+y2 equal to

x¯=6,σ2=94x<y4,5,6,6,7,8,,x,yx¯=36+x+y8x+y=12∑xi2n−x¯2=94x2+y2+2268=94+36x2+y2=80, xy=32X=4,y=8=x4+y2=256+64=320

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The mean and variance of the data 4, 5, 6, 6, 7, 8, x, y, where x<y are 6 and $\frac{9}{4}$ respectively. Then $x^{4} + y^{2}$ equal to

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Detailed Solution

$\bar{x} = 6, σ^{2} = \frac{9}{4} (x < y)$

4,5,6,6,7,8,,x,y

$\bar{x} = \frac{36 + x + y}{8}$

$x + y = 12$

$\frac{\sum x i^{2}}{n} - {(\bar{x})}^{2} = \frac{9}{4}$

$\frac{x^{2} + y^{2} + 226}{8} = \frac{9}{4} + 36$

$x^{2} + y^{2} = 80, x y = 32$

X=4,y=8

$= x^{4} + y^{2} = 256 + 64 = 320$

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The mean and variance of the data 4, 5, 6, 6, 7, 8, x, y, where x<y are 6 and 94 respectively. Then x4+y2 equal to

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The mean and variance of the data 4, 5, 6, 6, 7, 8, x, y, where x<y are 6 and $\frac{9}{4}$ respectively. Then $x^{4} + y^{2}$ equal to